Web31 jul. 2024 · Now, Equation of line PQ formed by joining the points P(1, 2) and Q(h, k) and having the slope – 3 is. y 2 – y 1 = m(x 2 – x 1) ⇒ k – 2 = (-3)(h – 1) ⇒ k – 2 = -3h + 3. ⇒ … WebThe closest point on the line should then be the midpoint of the point and its reflection. To do this for y = 3, your x-coordinate will stay the same for both points. The y-coordinate will be the midpoint, which is the average of the y-coordinates of our point and its reflection. (y1 + y2) / 2 = 3 y1 + y2 = 6 y2 = 6 - y1
Q. If Q is the image of the point P (2, 3, 4) under the reflection in ...
Web9 feb. 2024 · If the image of point P(1, 2, 3) about the plane 2x – y + 3y = 2 is Q, then the area of triangle PQR, asked 1 day ago in Mathematics by HemangRathore ( 50.0k … WebIt's being rotated around the origin (0,0) by 60 degrees. So if originally point P is right over here and we're rotating by positive 60 degrees, so that means we go counter clockwise by 60 degrees. So this looks like about 60 degrees right over here. One way to think about 60 degrees, is that that's 1/3 of 180 degrees. hospitals hoke county nc
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Web6 jan. 2024 · Hence, the image of P(1, 6, 3) in the given line is (1, 0, 7). ... Let P be the image of the point (3, 1, 7) with respect to the plane x – y + z = 3. Then the equation of the plane passing through. asked Jan 16, 2024 in Three … WebCorrect option is A) Any point Q on the given line is of the form (2r+1,−3r−1,8r−10). Direction ratios of PQ are. 2r+1−1,−3r−1−0,8r−10−0. i.e., 2r,−3r−1,8r−10. If Q is the foot … Web30 mrt. 2024 · Let line AB be x – 3y + 4 = 0 & point P be (1, 2) Let Q (h, k) be the image of point P (1, 2) in line AB Since line AB is mirror Point P & Q are at equal distance from line AB, i.e. PR = QR, i.e. R is the mid point of PQ Image is formed perpendicular to mirror i.e. line PQ is perpendicular to line AB Since R is the mid point of PQ We know that … psychological effect of trauma